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n^2+n-756=0
a = 1; b = 1; c = -756;
Δ = b2-4ac
Δ = 12-4·1·(-756)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-55}{2*1}=\frac{-56}{2} =-28 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+55}{2*1}=\frac{54}{2} =27 $
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